Python | hex() function

hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it’s corresponding hexadecimal form.

Syntax : 

hex(x) 
Parameters : 
x - an integer number (int object)
Returns :  Returns hexadecimal string.

Errors and Exceptions : 



TypeError :  Returns TypeError when anything other than
             integer type constants are passed as parameters.

 
Code #1 : Illustrates use of hex() function.

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# Python3 program to illustrate
# hex() function
  
print("The hexadecimal form of 23 is"
                            + hex(23))
                              
print("The hexadecimal form of the "
      "ascii value is 'a' is " + hex(ord('a')))
        
print("The hexadecimal form of 3.9 is "
                        + float.hex(3.9))

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Output :


The hexadecimal form of 23 is0x17
The hexadecimal form of the ascii value os 'a' is 0x61
The hexadecimal form of 3.9 is 0x1.f333333333333p+1


 

Code #2: Demontsrate TypeError when floating point values are passed as parameter.











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# hex() accepts only integer vaues as parameters 


print("The hexadecimal form of 11.1 is "


                            + hex(11.1)) 


  


''' 


# The hexadecimal conversion of floating   


# point integers can be done using the 


# function float.hex() 


print("The hexadecimal form of 11.1 is "  


                    + float.hex(11.1)) 


# Output : 


# The hexadecimal form of 11.1 is 0x1.6333333333333p+3 


  


# Similarly, float.hex() throws a TypeError 


# when integer values are passed in it.  


'''



















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Output :


Traceback (most recent call last):
  File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in 
    print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer



 

Applications :

hex() is used in all the standard conversions. For example conversion of hexadecimal to decimal, hexadecimal to octal, hexadecimal to binary.


Code #3 :











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# TypeConversion from decimal with base 10  


# to hexadecimal form with base 16 


  


  


# Taking input from user  


# an integer with base 10 


number = int(input("Enter a number with base 10\n")) 


  


# The choices present to the user 


print("a. Decimal to Hexadecimal ") 


print("b. Decimal to Octal") 


print("c. Decimal to Binary") 


  


# taking user input 


print("Enter your choice :- ") 


choice = input() 


  


# Running a variable choice 


# Hexadecimal form if choice 


# is set to 'a' 


if choice is 'a': 


  


    # lstrip helps remove "0x" from the left  


    # rstrip helps remove "L" from the right, 


    # L represents a long number 


    print("Hexadecimal form of " + str(number) + 


        " is " + hex(number).lstrip("0x").rstrip("L")) 


          


if choice is 'b': 


      


    # Octal representation is done 


    # by adding a prefix "0o"  


    print("Octal form of " + str(number) +


        " is " + oct(number).lstrip("0o").rstrip("L")) 


          


if choice is 'c': 


      


    # Binary representation is done by 


    # the addition of prefix "0b" 


    print("Binary form of " + str(number) + 


        " is "+bin(number).lstrip("0b").rstrip("L")) 



















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Output :


Enter a number with base 10
123
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice :- 
a
Hexadecimal form of 123 is 7b



Enter a number with base 10
123456789
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice :- 
a
Hexadecimal form of 123456789 is 75bcd15



          
          
          
          

            

    

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