Like array and linked list, the unrolled Linked List is also a linear data structure and is a variant of a linked list. Unlike a simple linked list, it stores multiple elements at each node. That is, instead of storing a single element at a node, unrolled linked lists store an array of elements at a node. The unrolled linked list covers the advantages of both array and linked list as it reduces the memory overhead in comparison to simple linked lists by storing multiple elements at each node and it also has the advantage of fast insertion and deletion as that of a linked list.

Advantages:
- Because of the Cache behavior, linear search is much faster in unrolled linked lists.
- In comparison to the ordinary linked list, it requires less storage space for pointers/references.
- It performs operations like insertion, deletion, and traversal more quickly than ordinary linked lists (because search is faster).
Disadvantages:
- The overhead per node is comparatively high than singly-linked lists. Refer to an example node in the below code.
Simple Implementation
The below program creates a simple unrolled linked list with 3 nodes containing a variable number of elements in each. It also traverses the created list.
C
// C program to implement unrolled linked list// and traversing it.#include<stdio.h>#include<stdlib.h>#define maxElements 4// Unrolled Linked List Nodestruct Node{ int numElements; int array[maxElements]; struct Node *next;};/* Function to traverse am unrolled linked list and print all the elements*/void printUnrolledList(struct Node *n){ while (n != NULL) { // Print elements in current node for (int i=0; i<n->numElements; i++) printf("%d ", n->array[i]); // Move to next node n = n->next; }}// Program to create an unrolled linked list// with 3 Nodesint main(){ struct Node* head = NULL; struct Node* second = NULL; struct Node* third = NULL; // allocate 3 Nodes head = (struct Node*)malloc(sizeof(struct Node)); second = (struct Node*)malloc(sizeof(struct Node)); third = (struct Node*)malloc(sizeof(struct Node)); // Let us put some values in second node (Number // of values must be less than or equal to // maxElement) head->numElements = 3; head->array[0] = 1; head->array[1] = 2; head->array[2] = 3; // Link first Node with the second Node head->next = second; // Let us put some values in second node (Number // of values must be less than or equal to // maxElement) second->numElements = 3; second->array[0] = 4; second->array[1] = 5; second->array[2] = 6; // Link second Node with the third Node second->next = third; // Let us put some values in third node (Number // of values must be less than or equal to // maxElement) third->numElements = 3; third->array[0] = 7; third->array[1] = 8; third->array[2] = 9; third->next = NULL; printUnrolledList(head); return 0;} |
C++
// C++ program to implement unrolled linked list // and traversing it. #include <bits/stdc++.h>using namespace std;#define maxElements 4 // Unrolled Linked List Node class Node { public: int numElements; int array[maxElements]; Node *next; }; /* Function to traverse am unrolled linked list and print all the elements*/void printUnrolledList(Node *n) { while (n != NULL) { // Print elements in current node for (int i=0; i<n->numElements; i++) cout<<n->array[i]<<" "; // Move to next node n = n->next; } } // Program to create an unrolled linked list // with 3 Nodes int main() { Node* head = NULL; Node* second = NULL; Node* third = NULL; // allocate 3 Nodes head = new Node(); second = new Node(); third = new Node(); // Let us put some values in second node (Number // of values must be less than or equal to // maxElement) head->numElements = 3; head->array[0] = 1; head->array[1] = 2; head->array[2] = 3; // Link first Node with the second Node head->next = second; // Let us put some values in second node (Number // of values must be less than or equal to // maxElement) second->numElements = 3; second->array[0] = 4; second->array[1] = 5; second->array[2] = 6; // Link second Node with the third Node second->next = third; // Let us put some values in third node (Number // of values must be less than or equal to // maxElement) third->numElements = 3; third->array[0] = 7; third->array[1] = 8; third->array[2] = 9; third->next = NULL; printUnrolledList(head); return 0; } // This is code is contributed by rathbhupendra |
Java
// Java program to implement unrolled// linked list and traversing it. import java.util.*;class GFG{ static final int maxElements = 4;// Unrolled Linked List Node static class Node { int numElements; int []array = new int[maxElements]; Node next; }; // Function to traverse am unrolled // linked list and print all the elementsstatic void printUnrolledList(Node n) { while (n != null) { // Print elements in current node for(int i = 0; i < n.numElements; i++) System.out.print(n.array[i] + " "); // Move to next node n = n.next; } } // Program to create an unrolled linked list // with 3 Nodes public static void main(String[] args) { Node head = null; Node second = null; Node third = null; // Allocate 3 Nodes head = new Node(); second = new Node(); third = new Node(); // Let us put some values in second // node (Number of values must be // less than or equal to maxElement) head.numElements = 3; head.array[0] = 1; head.array[1] = 2; head.array[2] = 3; // Link first Node with the // second Node head.next = second; // Let us put some values in // second node (Number of values // must be less than or equal to // maxElement) second.numElements = 3; second.array[0] = 4; second.array[1] = 5; second.array[2] = 6; // Link second Node with the third Node second.next = third; // Let us put some values in third // node (Number of values must be // less than or equal to maxElement) third.numElements = 3; third.array[0] = 7; third.array[1] = 8; third.array[2] = 9; third.next = null; printUnrolledList(head); } } // This code is contributed by amal kumar choubey |
C#
// C# program to implement unrolled// linked list and traversing it. using System;class GFG{ static readonly int maxElements = 4;// Unrolled Linked List Node class Node { public int numElements; public int []array = new int[maxElements]; public Node next; }; // Function to traverse am unrolled // linked list and print all the elementsstatic void printUnrolledList(Node n) { while (n != null) { // Print elements in current node for(int i = 0; i < n.numElements; i++) Console.Write(n.array[i] + " "); // Move to next node n = n.next; } } // Program to create an unrolled linked list // with 3 Nodes public static void Main(String[] args) { Node head = null; Node second = null; Node third = null; // Allocate 3 Nodes head = new Node(); second = new Node(); third = new Node(); // Let us put some values in second // node (Number of values must be // less than or equal to maxElement) head.numElements = 3; head.array[0] = 1; head.array[1] = 2; head.array[2] = 3; // Link first Node with the // second Node head.next = second; // Let us put some values in // second node (Number of values // must be less than or equal to // maxElement) second.numElements = 3; second.array[0] = 4; second.array[1] = 5; second.array[2] = 6; // Link second Node with the third Node second.next = third; // Let us put some values in third // node (Number of values must be // less than or equal to maxElement) third.numElements = 3; third.array[0] = 7; third.array[1] = 8; third.array[2] = 9; third.next = null; printUnrolledList(head); } } // This code is contributed by Rajput-Ji |
Output:
1 2 3 4 5 6 7 8 9
In this article, we have introduced an unrolled list and advantages of it. We have also shown how to traverse the list. In the next article, we will be discussing the insertion, deletion, and values of maxElements/numElements in detail.
Insertion in Unrolled Linked List
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