Given a text txt[0..n-1] and a pattern pat[0..m-1], write a function that prints all occurrences of pat[] in txt[]. You may assume that n > m.
Examples:
Input : txt[] = "geeks for geeks"
pat[] = "geeks"
Output : Pattern found at index 0
Pattern found at index 10
Input : txt[] = "aaaa"
pat[] = "aa"
Output : Pattern found at index 0
Pattern found at index 1
attern found at index 2
The idea is to use find() in C++ string class.
// CPP program to print all occurrences of a pattern // in a text #include <bits/stdc++.h> using namespace std; void printOccurrences(string txt, string pat) { int found = txt.find(pat); while (found != string::npos) { cout << "Pattern found at index " << found << endl; found = txt.find(pat, found + 1); } } int main() { string txt = "aaaa", pat = "aa"; printOccurrences(txt, pat); return 0; } |
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Output:
Pattern found at index 0 Pattern found at index 1 Pattern found at index 2
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