You are given two co-ordinates (x1, y1) and (x2, y2) of a two dimensional graph. Find the distance between them.
Examples:
Input : x1, y1 = (3, 4)
x2, y2 = (7, 7)
Output : 5
Input : x1, y1 = (3, 4)
x2, y2 = (4, 3)
Output : 1.41421
We will use the distance formula derived from Pythagorean theorem. The formula for distance between two point (x1, y1) and (x2, y2) is
Distance = 
We can get above formula by simply applying Pythagoras theorem
Below is the implementation of above idea.
C++
#include <bits/stdc++.h>using namespace std;// Function to calculate distancefloat distance(int x1, int y1, int x2, int y2){ // Calculating distance return sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) * 1.0);}// Drivers Codeint main(){ cout << distance(3, 4, 4, 3); return 0;} |
Java
// Java code to compute distanceclass GFG{ // Function to calculate distancestatic double distance(int x1, int y1, int x2, int y2){ // Calculating distance return Math.sqrt(Math.pow(x2 - x1, 2) + Math.pow(y2 - y1, 2) * 1.0);} //Driver code public static void main (String[] args) { System.out.println(Math.round(distance(3, 4, 4, 3)*100000.0)/100000.0); }}// This code is contributed by// Anant Agarwal. |
Python3
# Python3 program to calculate# distance between two pointsimport math# Function to calculate distancedef distance(x1 , y1 , x2 , y2): # Calculating distance return math.sqrt(math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2) * 1.0)# Drivers Codeprint("%.6f"%distance(3, 4, 4, 3))# This code is contributed by "Sharad_Bhardwaj". |
C#
// C# code to compute distanceusing System;class GFG{ // Function to calculate distance static double distance(int x1, int y1, int x2, int y2) { // Calculating distance return Math.Sqrt(Math.Pow(x2 - x1, 2) + Math.Pow(y2 - y1, 2) * 1.0); } // Driver code public static void Main () { Console.WriteLine(Math.Round(distance(3, 4, 4, 3) * 100000.0)/100000.0); }}// This code is contributed by// vt_m. |
PHP
<?php// PHP code to compute distance// Function to calculate distancefunction distance($x1, $y1, $x2, $y2){ // Calculating distance return sqrt(pow($x2 - $x1, 2) + pow($y2 - $y1, 2) * 1.0);}// Driver Codeecho(distance(3, 4, 4, 3));// This code is contributed by Ajit.?> |
Javascript
<script>// Function to calculate distancefunction distance(x1, y1, x2, y2){ // Calculating distance return Math.sqrt(Math.pow(x2 - x1, 2) + Math.pow(y2 - y1, 2) * 1.0);}// Drivers Codedocument.write(distance(3, 4, 4, 3));// This code is contributed by noob2000.</script> |
Output:
1.41421
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