Given a 26 letter character set, which is equivalent to character set of English alphabet i.e. (abcd….xyz) and act as a relation. We are also given several sentences and we have to translate them with the help of given new character set.
Examples:
New character set : qwertyuiopasdfghjklzxcvbnm Input : "utta" Output : geek Input : "egrt" Output : code
Idea behind conversion of new character set is to use hashing. Perform hashing of new character set where element of set is index and its position will be new alphabet value.
Approach1:
Given New character set = “qwertyuiopasdfghjklzxcvbnm”
- First character is q, during hashing we will place ‘a’ (for position ) at index q i.e. (17th).
- After hashing our new character set is “kvmcnophqrszyijadlegwbuft”.
- For input “egrt” =
hash[e -‘a’] = c
hash[g -‘a’] = o
hash[r -‘a’] = d
hash[t -‘a’] = eFor “egrt” is equivalent to “code”.
C++
// CPP program to change the sentence // with virtual dictionary #include<bits/stdc++.h> using namespace std; // Converts str to given character set void conversion(char charSet[], string &str;) { int n = str.length(); // hashing for new character set char hashChar[26]; for (int i = 0; i < 27; i++) hashChar[charSet[i]-'a'] = 'a' + i; // conversion of new character set for (int i = 0; i < n; i++) str[i] = hashChar[str[i]-'a']; } // Driver code int main() { char charSet[27] = "qwertyuiopasdfghjklzxcvbnm"; string str = "egrt"; conversion(charSet, str); cout << str; return 0; } |
Java
// Java program to change the sentence // with virtual dictionary class GFG { // Converts str to given character set static String conversion(char charSet[], String str) { int n = str.length(); // hashing for new character set char hashChar[] = new char[26]; for (int i = 0; i < 26; i++) { hashChar[Math.abs(charSet[i] - 'a')] = (char) ('a' + i); } // conversion of new character set String s=""; for (int i = 0; i < n; i++) { s += hashChar[str.charAt(i) - 'a']; } return s; } // Driver code public static void main(String[] args) { char charSet[] = "qwertyuiopasdfghjklzxcvbnm".toCharArray(); String str = "egrt"; str = conversion(charSet, str); System.out.println(str); // This code is contributed by princiRaj1992 } } |
C#
// C# program to change the sentence // with virtual dictionary using System; class GFG { // Converts str to given character set static String conversion(char []charSet, String str) { int n = str.Length; // hashing for new character set char []hashChar = new char[26]; for (int i = 0; i < 26; i++) { hashChar[Math.Abs(charSet[i] - 'a')] = (char) ('a' + i); } // conversion of new character set String s = ""; for (int i = 0; i < n; i++) { s += hashChar[str[i] - 'a']; } return s; } // Driver code public static void Main(String[] args) { char []charSet = "qwertyuiopasdfghjklzxcvbnm".ToCharArray(); String str = "egrt"; str = conversion(charSet, str); Console.WriteLine(str); } } // This code is contributed by Princi Singh |
Output:
code
Approach2:
1.Initialize two strings, one with actual set of alphabets and another with modified one.
2.Get the string to be converted from the user.
3.Retrive the first element of the string, find its index in the modified set of alphabets(eg:0 for ‘q’).
4.Find the element of same index in the actual set of alphabets and concatenate it with the result string.
5.Repeat the above steps for all the remaining elements of the input string.
6.Return the result string.
Java
// Java program to change the sentence // with virtual dictionary class GFG { static char[] alphabets = "abcdefghijklmnopqrstuvwxyz".toCharArray(); // function for converting the string static String conversion(String charSet, char[] str1) { String s2 = ""; for (char i : str1) // find the index of each element of the // string in the modified set of alphabets // replace the element with the one having the // same index in the actual set of alphabets s2 += alphabets[charSet.indexOf(i)]; return s2; } // Driver Code public static void main(String[] args) { String charSet = "qwertyuiopasdfghjklzxcvbnm"; String str1 = "egrt"; System.out.print(conversion(charSet, str1.toCharArray())); } } // This code is contributed by PrinciRaj1992 |
Python3
# Python3 program to change the sentence # with virtual dictionary #function for converting the string def conversion(charSet,str1): s2="" for i in str1: # find the index of each element of the # string in the modified set of alphabets # replace the element with the one having the # same index in the actual set of alphabets s2 += alphabets[charSet.index(i)] return s2 # Driver Code if __name__=='__main__': alphabets = "abcdefghijklmnopqrstuvwxyz" charSet= "qwertyuiopasdfghjklzxcvbnm" str1 = "egrt" print(conversion(charSet,str1)) #This code is contributed by PradeepEswar |
C#
// C# program to change the sentence // with virtual dictionary using System; class GFG { static char[] alphabets = "abcdefghijklmnopqrstuvwxyz".ToCharArray(); // function for converting the string static String conversion(String charSet, char[] str1) { String s2 = ""; foreach (char i in str1) // find the index of each element of the // string in the modified set of alphabets // replace the element with the one having the // same index in the actual set of alphabets s2 += alphabets[charSet.IndexOf(i)]; return s2; } // Driver Code public static void Main(String[] args) { String charSet = "qwertyuiopasdfghjklzxcvbnm"; String str1 = "egrt"; Console.Write(conversion(charSet, str1.ToCharArray())); } } // This code is contributed by Rajput-Ji |
Output:
code
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