Java | Exception Handling | Question 6
class Test{ public static void main(String[] args) { try { int a[]= {1, 2, 3, 4}; for (int i = 1; i <= 4; i++) { System.out.println ("a[" + i + "]=" + a[i] + "\n"); } } catch (Exception e) { System.out.println ("error = " + e); } catch (ArrayIndexOutOfBoundsException e) { System.out.println ("ArrayIndexOutOfBoundsException"); } }} |
(A) Compiler error
(B) Run time error
(C) ArrayIndexOutOfBoundsException
(D) Error Code is printed
(E) Array is printed
Answer: (A)
Explanation: ArrayIndexOutOfBoundsException has been already caught by base class Exception. When a subclass exception is mentioned after base class exception, then error occurs.
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