numpy.sqrt() in Python
numpy.sqrt(array[, out]) function is used to determine the positive square-root of an array, element-wise.
Syntax: numpy.sqrt()
Parameters:
array : [array_like] Input values whose square-roots have to be determined.
out : [ndarray, optional] Alternate array object in which to put the result; if provided, it must have the same shape as arr.Returns : [ndarray] Returns the square root of the number in an array.
Code #1 :
# Python program explaining# numpy.sqrt() method # importing numpyimport numpy as geek # applying sqrt() method on integer numbers arr1 = geek.sqrt([1, 4, 9, 16])arr2 = geek.sqrt([6, 10, 18]) print("square-root of an array1 : ", arr1)print("square-root of an array2 : ", arr2) |
Output:
square-root of an array1 : [ 1. 2. 3. 4.] square-root of an array2 : [ 2.44948974 3.16227766 4.24264069]
Code #2 :
# Python program explaining# numpy.sqrt() method # importing numpyimport numpy as geek # applying sqrt() method on complex numbersarr = geek.sqrt([4, -1, -5 + 9J]) print("square-root of an array : ", arr) |
Output:
square-root of an array : [ 2.00000000+0.j 0.00000000+1.j 1.62721083+2.76546833j]
Code #3 :
# Python program explaining# numpy.sqrt() method # importing numpyimport numpy as geek # applying sqrt() method on negative element of real numbers arr = geek.sqrt([-4, 5, -6]) print("square-root of an array : ", arr) |
Output:
RuntimeWarning: invalid value encountered in sqrt square-root of an array : [ nan 2.23606798 nan]
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