Python | Numpy numpy.ndarray.__pos__() Improve Improve Improve Like Article Like Save Article Save Share Report issue Report With the help of numpy.ndarray.__pos__() method of Numpy, one can multiply each and every element of an array with 1. Hence, the resultant array having values same as original array. Syntax: ndarray.__pos__($self, /) Return: +self Example #1 : In this example we can see that after applying numpy.__pos__(), we get the simple array that can be the same as original. # import the important module in python import numpy as np # make an array with numpy gfg = np.array([1, -2, 3, 4, 5, 6]) # applying numpy.__pos__() method print(gfg.__pos__()) Output: [ 1 -2 3 4 5 6] Example #2 : # import the important module in python import numpy as np # make an array with numpy gfg = np.array([[1, 2, -3, 4, 5, 6], [-6, 5, 4, 3, 2, -1]]) # applying numpy.__pos__() method print(gfg.__pos__()) Output: [[ 1 2 -3 4 5 6] [-6 5 4 3 2 -1]] Last Updated : 05 Mar, 2019 Like Article Save Article Previous Python | Numpy MaskedArray.__imod__ Next NumPy ndarray.__abs__() | Find Absolute Value of Elements in NumPy Array Share your thoughts in the comments Add Your Comment Please Login to comment...
