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numpy.not_equal() in Python

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  • Last Updated : 28 Mar, 2022

The numpy.not_equal() checks whether two element or unequal or not. Syntax : 

numpy.not_equal(x1, x2[, out])

Parameters : 

x1, x2 : [array_like]Input Array whose elements we want to check
out    : [ndarray, optional]Output array that returns True/False.
    A placeholder the same shape as x1 to store the result.

Return : 

Boolean array 

Code 1 : 

Python




# Python Program illustrating
# numpy.not_equal() method
  
import numpy as geek
 
= geek.not_equal([1., 2.], [1., 3.])
print("Not equal : \n", a, "\n")
 
b = geek.not_equal([1, 2], [[1, 3],[1, 4]])
print("Not equal : \n", b, "\n")

Output : 

Not equal : 
 [False  True] 

Not equal : 
 [[False  True]
 [False  True]] 

Code 2 : 

Python




# Python Program illustrating
# numpy.not_equal() method
   
import numpy as geek
 
# Here we will compare Complex values with int
a = geek.array([0 + 1j, 2])
b = geek.array([1,2])
 
= geek.not_equal(a, b)
print("Comparing complex with int using .not_equal() : ", d)

Output : 

Comparing complex with int using .not_equal() :  [ True False]

Code 3 : 

Python




# Python Program illustrating
# numpy.not_equal() method
   
import numpy as geek
 
# Here we will compare Float with int values
a = geek.array([1.1, 1])
b = geek.array([1, 2])
  
= geek.not_equal(a, b)
print("\nComparing float with int using .not_equal() : ", d)

Output : 

 Comparing float with int using .not_equal() :  [ True  True]

References : https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.not_equal.html Note :These codes won’t run on online IDE’s. So please, run them on your systems to explore the working. This article is contributed by Mohit Gupta_OMG ๐Ÿ˜€. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.


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