The numpy.less() : checks whether x1 is lesser than x2 or not. Syntax :
numpy.less(x1, x2[, out])
Parameters :
x1, x2 : [array_like]Input arrays. If x1.shape != x2.shape, they must be
broadcastable to a common shape
out : [ndarray, boolean]Array of bools, or a single bool if x1 and x2 are scalars.
Return :
Boolean array indicating results, whether x1 is lesser than x2 or not.
Code 1 :
Output :
Not equal :
[False True]
Not equal :
[[False True]
[False True]]
Is a lesser than b : [ True False]]
Code 2 :
Python
import numpy as geek
a = geek.array([1j,2])
b = geek.array([1,2])
print("Comparing complex with int : ", a < b)
d = geek.less(a, b)
print("\n Comparing complex with int .less() : ", d)
|
Output :
Comparing complex with int : [ True False]
Comparing complex with int .less() : [ True False]
Code 3 :
Python
import numpy as geek
a = geek.array([1.1, 1])
b = geek.array([1, 2])
print("Comparing float with int : ", a < b)
d = geek.less(a, b)
print("\n Comparing float with int using .less() : ", d)
|
Output :
Comparing float with int : [False True]
Comparing float with int using .less() : [False True]
References : https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.less.html#numpy.less Note : These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.
Don't miss your chance to ride the wave of the data revolution! Every industry is scaling new heights by tapping into the power of data. Sharpen your skills, become a part of the hottest trend in the 21st century.Dive into the future of technology - explore the
Complete Machine Learning and Data Science Program by GeeksforGeeks and stay ahead of the curve.
Commit to GfG's Three-90 Challenge! Purchase a course, complete 90% in 90 days, and save 90% cost click here to explore.
Last Updated :
28 Mar, 2022
Like Article
Save Article
Share your thoughts in the comments
Please Login to comment...