Program to Encrypt a String using ! and @

Given a string, the task is to encrypt this string using ! and @ symbols, alternatively. While encrypting the message the encrypted format must repeat the symbol as many times as the letter position in Alphabetical order.

Examples:

Input: string = "Ab" 
Output: !@@
Explanation:
Position of 'A' in alphabetical order is 1
and in String is odd position 
so encrypted message will have 1 '!'

Position of 'b' in alphabetical order is 2
and in String is even position 
so encrypted message will have 2 '@'

Therefore, the output "!@@"

Input: string = "CDE"
Output: !!!@@@@!!!!

Approach: This is a very basic and simple type of Encryption technique and can be done as follows:



  • Get the character one by one from the String
  • For each character, get the difference between the ASCII value of that character and ‘A'(if the character is a capital letter) or ‘a’ (if the letter is a small letter). This will be the number of times the encryption character is to be repeated.
  • For the ith character of the string, if i is odd, the encryption character will be ‘!’ and if i is even, the encryption character will be ‘@’.

Below is the implementation of the above code:

C

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// C program to Encrypt the String
// using ! and @
  
#include <stdio.h>
#include <string.h>
  
// Function to encrypt the string
void encrypt(char input[100])
{
  
    // evenPos is for storing encrypting
    // char at evenPosition
    // oddPos is for storing encrypting
    // char at oddPosition
    char evenPos = '@', oddPos = '!';
  
    int repeat, ascii;
  
    for (int i = 0; i <= strlen(input); i++) {
  
        // Get the number of times the character
        // is to be repeated
        ascii = input[i];
        repeat = ascii >= 97 ? ascii - 96 : ascii - 64;
  
        for (int j = 0; j < repeat; j++) {
            // if i is odd, print '!'
            // else print '@'
            if (i % 2 == 0)
                printf("%c", oddPos);
            else
                printf("%c", evenPos);
        }
    }
}
  
// Driver code
void main()
{
    char input[100] = { 'A', 'b', 'C', 'd' };
  
    // Encrypt the String
    encrypt(input);
}

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Java














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// Java program to Encrypt the String 


// using ! and @ 


class GFG  


{ 


  


// Function to encrypt the string 


static void encrypt(char input[]) 


{ 


  


    // evenPos is for storing encrypting 


    // char at evenPosition 


    // oddPos is for storing encrypting 


    // char at oddPosition 


    char evenPos = '@', oddPos = '!'; 


  


    int repeat, ascii; 


  


    for (int i = 0; i < input.length; i++) 


    { 


  


        // Get the number of times the character 


        // is to be repeated 


        ascii = input[i]; 


        repeat = ascii >= 97 ?  


                  ascii - 96 : ascii - 64; 


  


        for (int j = 0; j < repeat; j++) 


        { 


            // if i is odd, print '!' 


            // else print '@' 


            if (i % 2 == 0) 


                System.out.printf("%c", oddPos); 


            else


                System.out.printf("%c", evenPos); 


        } 


    } 


} 


  


// Driver code 


public static void main(String[] args) 


{ 


    char input[] = { 'A', 'b', 'C', 'd' }; 


  


    // Encrypt the String 


    encrypt(input); 


} 


}  


  


// This code is contributed by PrinciRaj1992 



















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Python3














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# Python3 program to Encrypt the String  


# using ! and @  


  


# Function to encrypt the string  


def encrypt(input_arr) : 


  


    # evenPos is for storing encrypting  


    # char at evenPosition  


    # oddPos is for storing encrypting  


    # char at oddPosition  


    evenPos = '@'; oddPos = '!';  


  


    for i in range(len(input_arr)) : 


  


        # Get the number of times the character  


        # is to be repeated  


        ascii = ord(input_arr[i]);  


        repeat = (ascii - 96 ) if ascii >= 97 \ 


                               else (ascii - 64);  


  


        for j in range(repeat) : 


              


            # if i is odd, print '!'  


            # else print '@'  


            if (i % 2 == 0) : 


                print(oddPos, end = "");  


            else : 


                print(evenPos, end = "");  


  


# Driver code  


if __name__ == "__main__" :  


  


    input_arr = [ 'A', 'b', 'C', 'd' ];  


  


    # Encrypt the String  


    encrypt(input_arr);  


      


# This code is contributed by AnkitRai01 



















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C#














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// C# program to Encrypt the String 


// using ! and @ 


using System; 


using System.Collections.Generic; 


  


class GFG  


{ 


  


// Function to encrypt the string 


static void encrypt(char []input) 


{ 


  


    // evenPos is for storing encrypting 


    // char at evenPosition 


    // oddPos is for storing encrypting 


    // char at oddPosition 


    char evenPos = '@', oddPos = '!'; 


  


    int repeat, ascii; 


  


    for (int i = 0; i < input.Length; i++) 


    { 


  


        // Get the number of times the character 


        // is to be repeated 


        ascii = input[i]; 


        repeat = ascii >= 97 ?  


                ascii - 96 : ascii - 64; 


  


        for (int j = 0; j < repeat; j++) 


        { 


            // if i is odd, print '!' 


            // else print '@' 


            if (i % 2 == 0) 


                Console.Write("{0}", oddPos); 


            else


                Console.Write("{0}", evenPos); 


        } 


    } 


} 


  


// Driver code 


public static void Main(String[] args) 


{ 


    char []input = { 'A', 'b', 'C', 'd' }; 


  


    // Encrypt the String 


    encrypt(input); 


} 


}  


  


// This code is contributed by 29AjayKumar 



















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Output:


!@@!!!@@@@






          
          
          
          

            

    

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