Given a string, the task is to check if every vowel is present or not. We consider a vowel to be present if it is present in upper case or lower case. i.e. ‘a’, ‘e’, ‘i’.’o’, ‘u’ or ‘A’, ‘E’, ‘I’, ‘O’, ‘U’ .
Examples :
Input : geeksforgeeks Output : Not Accepted All vowels except 'o' are not present Input : ABeeIghiObhkUul Output : Accepted All vowels are present
Approach : Firstly, create set of vowels using set() function. Check for each character of the string is vowel or not, if vowel then add into the set s. After coming out of the loop, check length of the set s, if length of set s is equal to the length of the vowels set then string is accepted otherwise not.
Below is the implementation :
# Python program to accept the strings# which contains all the vowels# Function for check if string# is accepted or notdef check(string) :
string = string.lower()
# set() function convert "aeiou"
# string into set of characters
# i.e.vowels = {'a', 'e', 'i', 'o', 'u'}
vowels = set("aeiou")
# set() function convert empty
# dictionary into empty set
s = set({})
# looping through each
# character of the string
for char in string :
# Check for the character is present inside
# the vowels set or not. If present, then
# add into the set s by using add method
if char in vowels :
s.add(char)
else:
pass
# check the length of set s equal to length
# of vowels set or not. If equal, string is
# accepted otherwise not
if len(s) == len(vowels) :
print("Accepted")
else :
print("Not Accepted")
# Driver codeif __name__ == "__main__" :
string = "SEEquoiaL"
# calling function
check(string)
|
Accepted
Alternate Implementation :
def check(string):
string = string.replace(' ', '')
string = string.lower()
vowel = [string.count('a'), string.count('e'), string.count(
'i'), string.count('o'), string.count('u')]
# If 0 is present int vowel count array
if vowel.count(0) > 0:
return('not accepted')
else:
return('accepted')
# Driver codeif __name__ == "__main__":
string = "SEEquoiaL"
print(check(string))
|
accepted
Alternate Implementation 2.0 :
# Python program for the above approachdef check(string):
if len(set(string.lower()).intersection("aeiou")) >= 5:
return ('accepted')
else:
return ("not accepted")
# Driver codeif __name__ == "__main__":
string = "geeksforgeeks"
print(check(string))
|
not accepted
Alternate Implementation 3.0 (Using Regular Expressions):
- Compile a regular expression using compile() for “character is not a, e, i, o and u”.
- Use re.findall() to fetch the strings satisfying the above regular expression.
- Print output based on the result.
#import libraryimport re
sampleInput = "aeioAEiuioea"
# regular expression to find the strings # which have characters other than a,e,i,o and uc = re.compile('[^aeiouAEIOU]')
# use findall() to get the list of strings# that have characters other than a,e,i,o and u.if(len(c.findall(sampleInput))):
print("Not Accepted") # if length of list > 0 then it is not accepted
else:
print("Accepted") # if length of list = 0 then it is accepted
|
Accepted
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