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Python Dictionary copy()
Python Dictionary copy() method returns a shallow copy of the dictionary.
Python Dictionary copy() Syntax:
dict.copy()
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Python Dictionary copy() Parameters:
The copy() method doesn’t take any parameters.
Python Dictionary copy() Returns:
This method doesn’t modify the original, dictionary just returns copy of the dictionary.
Python Dictionary copy() Examples:
Input : original = {1:'geeks', 2:'for'}
new = original.copy()
Output : original: {1: 'one', 2: 'two'}
new: {1: 'one', 2: 'two'}Python Dictionary copy() Error:
As we are not passing any parameters there is no chance of any error.
Example 1: Working with Python Dictionary copy()
Python3
# Python program to demonstrate working# of dictionary copyoriginal = {1: 'geeks', 2: 'for'}# copying using copy() functionnew = original.copy()# removing all elements from the list# Only new list becomes empty as copy()# does shallow copy.new.clear()print('new: ', new)print('original: ', original) |
Output:
new: {}
original: {1: 'geeks', 2: 'for'}Example 2: Python Dictionary copy() and update
Python3
# given dictionarydict1 = {10: 'a', 20: [1, 2, 3], 30: 'c'}print("Given Dictionary:", dict1)# new dictionary and# copying using copy() methoddict2 = dict1.copy()print("New copy:", dict2)# Updating dict2 elements and# checking the change in dict1dict2[10] = 10dict2[20][2] = '45' # list item updatedprint("Updated copy:", dict2) |
Output:
Given Dictionary: {10: 'a', 20: [1, 2, 3], 30: 'c'}
New copy: {10: 'a', 20: [1, 2, 3], 30: 'c'}
Updated copy: {10: 10, 20: [1, 2, '45'], 30: 'c'}How is it different from simple assignment “=”?
Unlike copy(), the assignment operator does deep copy.
Python3
# Python program to demonstrate difference# between = and copy()original = {1: 'geeks', 2: 'for'}# copying using copy() functionnew = original.copy()# removing all elements from new list# and printing bothnew.clear()print('new: ', new)print('original: ', original)original = {1: 'one', 2: 'two'}# copying using =new = original# removing all elements from new list# and printing bothnew.clear()print('new: ', new)print('original: ', original) |
Output:
new: {}
original: {1: 'geeks', 2: 'for'}
new: {}
original: {}
