1826 Maryland gubernatorial election
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January 2, 1826
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 Government |
The 1826 Maryland gubernatorial election was held on January 2, 1826, in order to elect the Governor of Maryland. Democratic-Republican nominee and incumbent member of the U.S. House of Representatives from Maryland's 2nd district Joseph Kent was elected by the Maryland General Assembly against candidates William Tyler and Thomas H. Carroll.[1]
General election
[edit]On election day, January 2, 1826, Democratic-Republican nominee Joseph Kent was elected by the Maryland General Assembly, thereby retaining Democratic-Republican control over the office of governor. Kent was sworn in as the 19th Governor of Maryland on January 9, 1826.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Joseph Kent | 59 | 65.56 | |
| William Tyler | 30 | 33.33 | ||
| Thomas H. Carroll | 1 | 1.11 | ||
| Total votes | 90 | 100.00 | ||
| Democratic-Republican hold | ||||
References
[edit]- ↑ "Joseph Kent". National Governors Association. Retrieved 2024-04-27.
- ↑ "MD Governor". ourcampaigns.com. March 28, 2005. Retrieved 2024-04-27.
